Given below are two quantities named I and II. Based on the given information, you have to determine the relation between the two quantities. You should use the given data and your knowledge of Mathematics to choose among the possible answers.

A man has two balls. The ratio of radius of first ball to that of the second ball is 7 : 3.

Quantity I: If man cut the first ball from middle and difference between total surface area of part of first ball and total surface area of second ball is 1538.46cm^{2}, then find the radius of smaller ball.

Option 2 : If Quantity I < Quantity II

Let the radius of first ball be 7x and second ball be 3x.

**Quantity I:**

When man cut ball, it’s become a hemisphere

So, 3πr^{2} – 4πr^{2} = 1538.46cm^{2}

22/7 [(3 × (7x)^{2}) – (4 × (3x)^{2})] = 1538.46

22/7 [111x^{2}] = 1538.46

x^{2 }= 4.41

x = 2.1

The radius of smaller ball = 3x = 3 × 2.1 = 6.3 cm

**Quantity II:**

Given that, sum of radius of two ball = 30

7x + 3x = 30

⇒ x = 3

Radius of first ball = 7x = 7 × 3 = 21

Hence, Quantity I < Quantity II